Q.
The readings shown in two spring balances $S_{1}$ and $S_{2}$ are $90 \,kg$ and $30 \,kg$, respectively, and the lift is accelerating upwards with an acceleration of $10 \,m / s ^{2}$. If the mass is stationary with respect to the lift, then the mass (in $kg$ ) of -the block will be
Laws of Motion
Solution:
$T_{1}-T_{2}-m g-m a=0$
$T_{1}-T_{2}=m(g+a)$
$600=m(10+10)$
$\Rightarrow m=30 \,kg$
