Zinc dissolves in excess of aqueous alkali Zn+2OH−+2H2O→Tetrahydroxozincate(II) ion[Zn(OH)4]2−+H2↑
However, this reaction in NCERT is given as Zn+2NaOH→Na2ZnO2+H2↑ ZnO22− is anhydrous form of [Zn(OH)4]2−
So in aqueous medium best answer of this question is [Zn(OH)4]2−