The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction 1 mol of ' A' with excess of AgNO 3 in aqueous medium gives mol ( s ) of Ag. (Round off to the Nearest Integer).

Question

The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction 1 mol of ' A' with excess of AgNO 3 in aqueous medium gives mol ( s ) of Ag. (Round off to the Nearest Integer). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P 4+3 OH -+3 H 2 O arrow PH 3+ underset( A )3 H 2 PO 2- underset1 textmoleH 2 PO 2-+ underset text excess4 Ag ++2 H 2 O arrow underset4 text excess4Ag+ H 3 PO 4+3 H +

Q. The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product ' $A$ '. The reaction $1 m o l$ of ' $A$ ' with excess of $A g N O_{3}$ in aqueous medium gives $m o l (s)$ of $A g$ . (Round off to the Nearest Integer).

$P_{4} + 3 O H^{-} + 3 H_{2} O \to P H_{3} + (A) 3 H_{2} P O_{2}^{-}$

$1 mole H_{2} P O_{2}^{-} + excess 4 A g^{+} + 2 H_{2} O \to 4 excess 4 A g + H_{3} P O_{4} + 3 H^{+}$

Q. The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction 1mol of ' A' with excess of AgNO3​ in aqueous medium gives mol(s) of Ag. (Round off to the Nearest Integer).

P4​+3OH−+3H2​O→PH3​+(A)3H2​PO2−​​ 1moleH2​PO2−​​+ excess4Ag+​+2H2​O→4 excess4Ag​+H3​PO4​+3H+

Q. The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product ' $A$ '. The reaction $1 m o l$ of ' $A$ ' with excess of $A g N O_{3}$ in aqueous medium gives $m o l (s)$ of $A g$ . (Round off to the Nearest Integer).

$P_{4} + 3 O H^{-} + 3 H_{2} O \to P H_{3} + (A) 3 H_{2} P O_{2}^{-}$

$1 mole H_{2} P O_{2}^{-} + excess 4 A g^{+} + 2 H_{2} O \to 4 excess 4 A g + H_{3} P O_{4} + 3 H^{+}$