Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The reaction of sulphur in alkaline medium is the below: S 8( s )+ a OH -( aq ) arrow b S 2-( aq )+ c S 2 O 3 2-( aq )+ d H 2 O (ℓ) The values of 'a' is
Q. The reaction of sulphur in alkaline medium is the below:
S
8
(
s
)
+
a
O
H
(
a
q
)
−
→
b
S
(
a
q
)
2
−
+
c
S
2
O
3
2
−
(
a
q
)
+
d
H
2
O
(
ℓ
)
The values of '
a
' is
4752
167
JEE Main
JEE Main 2021
Redox Reactions
Report Error
Answer:
12
Solution:
for balancing in basic medium add equal number of
O
H
⊖
that of
H
+
2
S
8
+
12
H
2
O
+
24
O
H
⊖
⟶
8
S
2
−
+
4
S
2
O
8
2
−
+
24
H
2
O
2
S
8
+
24
O
H
⊖
→
8
S
2
−
+
4
S
2
O
8
2
−
+
12
H
2
O
S
8
+
12
O
H
⊖
→
4
S
2
−
+
2
S
2
O
8
2
−
+
6
H
2
O
a
=
12