The reaction of solid XeF2 with AsF5 in 1:1 ratio affords

Question

The reaction of solid XeF2 with AsF5 in 1:1 ratio affords (A) XeF4 and AsF3 (B) XeF6 and AsF3 (C) [X e F]+[A s F6]- (D) [.Xe2F3].+[.AsF6].-

Tardigrade Admin · Accepted Answer

XeF2 (Xenon difluoride) acts as a fluoride donor and thus, forms complex when mixed with covalent pentafluorides like AsF5 . underset1X e F2+ underset1A s F5 arrow [X e F]+[A s F6]-

Q. The reaction of solid $X e F_{2}$ with $A s F_{5}$ in 1:1 ratio affords

$X e F_{4}$ and $A s F_{3}$

$X e F_{6}$ and $A s F_{3}$

$[X e F]^{+} [A s F_{6}]^{-}$

$[X e_{2} F_{3}]^{+} [A s F_{6}]^{-}$

$X e F_{2}$ (Xenon difluoride) acts as a fluoride donor and thus, forms complex when mixed with covalent pentafluorides like $A s F_{5}$ .

$1 X e F_{2} + 1 A s F_{5} \to [X e F]^{+} [A s F_{6}]^{-}$

Q. The reaction of solid XeF2​ with AsF5​ in 1:1 ratio affords

XeF4​ and AsF3​

XeF6​ and AsF3​

[XeF]+[AsF6​]−

[Xe2​F3​]+[AsF6​]−