Question

The reaction of solid $XeF_{2}$ with $AsF_{5}$ in 1:1 ratio affords

• A. $XeF_{4}$ and $AsF_{3}$
• B. $XeF_{6}$ and $AsF_{3}$
• C. $\left[X e F\right]^{+}\left[A s F_{6}\right]^{-}$
• D. $\left[\right.Xe_{2}F_{3}\left]\right.^{+}\left[\right.AsF_{6}\left]\right.^{-}$

Answer 1

Answer: (C)

$XeF_{2}$ (Xenon difluoride) acts as a fluoride donor and thus, forms complex when mixed with covalent pentafluorides like $AsF_{5}$ .

$\underset{1}{X e F_{2}}+\underset{1}{A s F_{5}} \rightarrow \left[X e F\right]^{+}\left[A s F_{6}\right]^{-}$