The reaction of RCONH2 with a mixture of Br2 and aqueous KOH gives RNH2 as the main product. The intermediate not involved in this reaction is (are):

Question

The reaction of RCONH2 with a mixture of Br2 and aqueous KOH gives RNH2 as the main product. The intermediate not involved in this reaction is (are): (A) RCONHBr (B) RCON-BrK+ (C) R-N=C=O (D) RCONBr2

Tardigrade Admin · Accepted Answer

This is Hofmann bromamide reaction and RCONBr2 does not form in this reaction. See mechanism for it: RCO-NH2+Br2+4KOH arrow R-NH2+K2CO3+2KBr+2H2O Solution

Q. The reaction of $RCON H_{2}$ with a mixture of $B r_{2}$ and aqueous $K O H$ gives $RN H_{2}$ as the main product. The intermediate not involved in this reaction is (are):

$RCON H B r$

$RCO N^{-} B r K^{+}$

$R - N = C = O$

$RCONB r_{2}$

This is Hofmann bromamide reaction and $RCONB r_{2}$ does not form in this reaction. See mechanism for it:

$RCO - N H_{2} + B r_{2} + 4 K O H \to R - N H_{2} + K_{2} C O_{3} + 2 K B r + 2 H_{2} O$

Q. The reaction of RCONH2​ with a mixture of Br2​ and aqueous KOH gives RNH2​ as the main product. The intermediate not involved in this reaction is (are):

RCONHBr

RCON−BrK+

R−N=C=O

RCONBr2​