The reaction of propene with HOCl proceeds via the addition of

Question

The reaction of propene with HOCl proceeds via the addition of (A) H+ in the first step (B) Cl+ in the first step (C) OH- in the first step (D) Cl+ and OH- single step

Tardigrade Admin · Accepted Answer

HOCl longrightarrow HO- + Cl+ i.e. reaction is initiated by Cl +(chloronium ion electrophile)

Q. The reaction of propene with $H OCl$ proceeds via the addition of

$H^{+}$ in the first step

$C l^{+}$ in the first step

$O H^{-}$ in the first step

$C l^{+}$ and $O H^{-}$ single step

$H OCl ⟶ H O^{-} + C l^{+}$
i.e. reaction is initiated by $C l^{+}$ (chloronium ion electrophile)

Q. The reaction of propene with HOCl proceeds via the addition of

H+ in the first step

Cl+ in the first step

OH− in the first step

Cl+ and OH− single step