The reaction N 2 O 5( g ) leftharpoons 2 NO 2( g )+(1/2) O 2( g ) is started with initial pressure of N 2 O 5( g ) equal to 600 torr. What fraction of N 2 O 5 (g) decomposed when total pressure of the system is 960 torr?

Question

The reaction N 2 O 5( g ) leftharpoons 2 NO 2( g )+(1/2) O 2( g ) is started with initial pressure of N 2 O 5( g ) equal to 600 torr. What fraction of N 2 O 5 (g) decomposed when total pressure of the system is 960 torr? (A) 0.05 (B) 0.1 (C) 0.2 (D) 0.4

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/d7409b742df91abb4e7f21246f1ff004-.png" /> At equilibrium: Total press is (600+(3 p/2)) torr ∴ 600+(3 p/2)=960 or (3 p/2)=360 or p=240 torr ∴ Fraction of N 2 O 5( g ) decomposed =(240/600)=0.4

Q. The reaction $N_{2} O_{5} (g) ⇌ 2 N O_{2} (g) + \frac{1}{2} O_{2} (g)$ is started with initial pressure of $N_{2} O_{5} (g)$ equal to $600$ torr. What fraction of $N_{2} O_{5}$ (g) decomposed when total pressure of the system is $960$ torr?

$0.05$

$0.1$

$0.2$

$0.4$

At equilibrium:
Total press is $(600 + \frac{3 p}{2})$ torr
$∴ 600 + \frac{3 p}{2} = 960$
or $\frac{3 p}{2} = 360$
or $p = 240$ torr
$∴$ Fraction of $N_{2} O_{5} (g)$ decomposed $= \frac{240}{600} = 0.4$

Q. The reaction N2​O5​(g)⇌2NO2​(g)+21​O2​(g) is started with initial pressure of N2​O5​(g) equal to 600 torr. What fraction of N2​O5​ (g) decomposed when total pressure of the system is 960 torr?

0.05

0.1

0.2

0.4