Tardigrade
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Tardigrade
Question
Chemistry
The reaction, MgO(s) + C(s) arrow Mg(S) + CO(g) , for which ΔrH° = + 491.1 kJ mol-1 and ΔrS° = 198.0 JK-1 mol- 1, is not feasible at 298 K. Temperature above which reaction will be feasible is :
Q. The reaction,
M
g
O
(
s
)
+
C
(
s
)
→
M
g
(
S
)
+
CO
(
g
)
, for which
Δ
r
H
∘
=
+
491.1
k
J
m
o
l
−
1
and
Δ
r
S
∘
=
198.0
J
K
−
1
m
o
l
−
1
, is not feasible at
298
K
. Temperature above which reaction will be feasible is :
2496
226
JEE Main
JEE Main 2019
Thermodynamics
Report Error
A
1890.0
K
15%
B
2480.3
K
72%
C
2040.5
K
7%
D
2380.5
K
6%
Solution:
T
e
q
=
Δ
S
Δ
H
=
198
491.1
×
1000
=
2480.3
K