The reaction follows the mechanism A + B xrightleftharpoons[k-1]k1AB (fast) AB + B xrightarrow k2 A + B2 (slow) then rate law is

Question

The reaction follows the mechanism A + B xrightleftharpoons[k-1]k1AB (fast) AB + B xrightarrow k2 A + B2 (slow) then rate law is (A) r = k [A][B] (B) r = k [AB][B] (C) r = k [A][B]2 (D) r = k [A]2 [B]

Tardigrade Admin · Accepted Answer

Mechanism, A + B xrightleftharpoons[k-1]k1AB (fast) AB + B xrightarrow k2 A + B2 (slow) For fast reaction (steady state step) k1 [A][B] = k-1 [AB] [AB] = (k1 [A][B]/k-1) The value of [AB] put into rate law Rate law = (k2 k1/k-1) [A] [B]2 = k [A][B]2

Q. The reaction follows the mechanism
$A + B k_{1} k_{- 1} A B (f a s t)$ $A B + B k_{2} A + B_{2} (s l o w)$
then rate law is

$r = k [A] [B]$

$r = k [A B] [B]$

$r = k [A] [B]^{2}$

$r = k [A]^{2} [B]$

Q. The reaction follows the mechanism A+Bk1​k−1​​AB(fast) AB+Bk2​​A+B2​(slow) then rate law is

r=k[A][B]

r=k[AB][B]

r=k[A][B]2

r=k[A]2[B]

Mechanism, A+Bk1​k−1​​AB(fast) AB+Bk2​​A+B2​(slow) For fast reaction (steady state step) k1​[A][B]=k−1​[AB] [AB]=k−1​k1​[A][B]​ The value of [AB] put into rate law Ratelaw=k−1​k2​k1​​[A][B]2 =k[A][B]2

Q. The reaction follows the mechanism
$A + B k_{1} k_{- 1} A B (f a s t)$ $A B + B k_{2} A + B_{2} (s l o w)$
then rate law is

$r = k [A] [B]$

$r = k [A B] [B]$

$r = k [A] [B]^{2}$

$r = k [A]^{2} [B]$