The reaction B(OH)3 + NaOH leftharpoons Na[B(OH)4] B(OH)3 + NaOH leftharpoons NaBO2 + 2 H2O can be made to proceed to forward direction by the addition of

Question

The reaction B(OH)3 + NaOH leftharpoons Na[B(OH)4] B(OH)3 + NaOH leftharpoons NaBO2 + 2 H2O can be made to proceed to forward direction by the addition of (A) borax (B) cis-l, 2 diol (C) trans-1, 2 diol (D) Na2HPO4

Tardigrade Admin · Accepted Answer

B(OH)3 behaves as a weak monobasic acid. However, when cis-diol is added to the titration solution, it forms a very stable complex with [B(OH)4]- formed by the forward reaction, thus effectively removing it from solution. This upsets the balance of the equation and the reaction proceeds completely to the right. Thus all the B(OH)3 reacts with NaOH and it acts as a strong acid in the presence of the cis-diol

Q. The reaction
$B (O H)_{3} + N a O H ⇌ N a [B (O H)_{4}]$
$B (O H)_{3} + N a O H ⇌ N a B O_{2} + 2 H_{2} O$
can be made to proceed to forward direction by the addition of

borax

cis-l, 2 diol

trans-1, 2 diol

$N a_{2} H P O_{4}$

Q. The reaction B(OH)3​+NaOH⇌Na[B(OH)4​] B(OH)3​+NaOH⇌NaBO2​+2H2​O can be made to proceed to forward direction by the addition of

borax

cis-l, 2 diol

trans-1, 2 diol

Na2​HPO4​

Q. The reaction
$B (O H)_{3} + N a O H ⇌ N a [B (O H)_{4}]$
$B (O H)_{3} + N a O H ⇌ N a B O_{2} + 2 H_{2} O$
can be made to proceed to forward direction by the addition of

$N a_{2} H P O_{4}$