The reaction, A + B +C arrow Z occurs by the following mechanism (i) A + B arrow X (fast) (ii) X + C arrow Y (slow) (iii) Y + B arrow Z (very fast) Rate law for this reaction is

Question

The reaction, A + B +C arrow Z occurs by the following mechanism (i) A + B arrow X (fast) (ii) X + C arrow Y (slow) (iii) Y + B arrow Z (very fast) Rate law for this reaction is (A)  k[C]  (B)  k[A][B]2[C]  (C)  k[Z]  (D)  k[X][Y][Z]

Tardigrade Admin · Accepted Answer

The slowest step is the rate determining step in the multiple step reaction. So, rate expression is k[C] .

Q. The reaction, $A + B + C \to Z$ occurs by the following mechanism
(i) $A + B \to X$ (fast)
(ii) $X + C \to Y$ (slow)
(iii) $Y + B \to Z$ (very fast)
Rate law for this reaction is

$k [C]$

$k [A] [B]^{2} [C]$

$k [Z]$

$k [X] [Y] [Z]$

The slowest step is the rate determining step in the multiple step reaction. So, rate expression is $k [C]$ .

Q. The reaction, A+B+C→Z occurs by the following mechanism (i) A+B→X (fast) (ii) X+C→Y (slow) (iii) Y+B→Z (very fast) Rate law for this reaction is

k[C]

k[A][B]2[C]

k[Z]

k[X][Y][Z]