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Tardigrade
Question
Chemistry
The reaction A+2B+C→ Z occurs by the following mechanism: (i) A+B xrightarrow''X'' (fast) (ii) X+C xrightarrowY (slow) (iii) V+B xrightarrowX (very fast) Rate law for this reaction is:
Q. The reaction
A
+
2
B
+
C
→
Z
occurs by the following mechanism : (i)
A
+
B
′′
X
′′
(fast) (ii)
X
+
C
Y
(slow) (iii)
V
+
B
X
(very fast) Rate law for this reaction is:
2493
204
Haryana PMT
Haryana PMT 1999
Report Error
A
K
[
X
]
[
Y
]
[
Z
]
B
K
[
Z
]
C
K
[
A
]
[
B
]
2
[
C
]
D
K
[
C
]
Solution:
Slow step is the rate determining step of the reaction only in step (ii) the reaction 'C' is involved in the slow step.