The reaction,2SO2(g) + O2(g) rightharpoons 2SO3(g) is carried out in a 1 dm3 vessel and 2 dm3 vessel separately. The ratio of the reaction velocities will be :

Question

The reaction,2SO2(g) + O2(g) rightharpoons 2SO3(g) is carried out in a 1 dm3 vessel and 2 dm3 vessel separately. The ratio of the reaction velocities will be : (A) 4: 1 (B) 8: 1 (C) 1: 8 (D) 1: 4

Tardigrade Admin · Accepted Answer

2 mathrmSO2( mathrm~g)+ mathrmO2( mathrm~g) leftharpoons 2 mathrmSO3( mathrm~g) For this reaction, rate mathrmr1= mathrmk[ mathrmSO2]2[ mathrmO2] On doubling the volume of vessel, concentration would be half. Hence, Rate( mathrmr2)= mathrmk(([ mathrmSO2]/2))2(([ mathrmO2]/2))=( mathrmr1/8) (r1/r2)=8: 1

Q. The reaction, $2 S O_{2 (g)} + O_{2 (g)} ⇋ 2 S O_{3 (g)}$ is carried out in a $1 d m^{3}$ vessel and $2 d m^{3}$ vessel separately. The ratio of the reaction velocities will be :

4 : 1

8 : 1

1 : 8

1 : 4

$2 SO_{2} (g) + O_{2} (g) ⇌ 2 SO_{3} (g)$

For this reaction, rate

$r_{1} = k [SO_{2}]^{2} [O_{2}]$

On doubling the volume of vessel, concentration would be half.

Hence, Rate $(r_{2}) = k (\frac{[ SO _{2} ]}{2})^{2} (\frac{[ O _{2} ]}{2}) = \frac{r _{1}}{8}$

$\frac{r _{1}}{r _{2}} = 8 : 1$

Q. The reaction,2SO2(g)​+O2(g)​⇋2SO3(g)​ is carried out in a 1dm3 vessel and 2dm3 vessel separately. The ratio of the reaction velocities will be :