The ratio of the nuclear radii of elements with mass numbers 216 and 125 is

Question

The ratio of the nuclear radii of elements with mass numbers 216 and 125 is (A) 216: 125 (B) √ 216: √ 125 (C) 6: 5 (D) none of these

Tardigrade Admin · Accepted Answer

Nuclear radius is proportional to A1 / 3, where A is the mass number of nucleus. R=R0 A1 / 3 where R0=1.2 fm (R1/R2)=(R0(216)1 / 3/R0(125)1 / 3)=(6/5)

Q. The ratio of the nuclear radii of elements with mass numbers $216$ and $125$ is

$216 : 125$

$216 : 125$

$6 : 5$

none of these

Nuclear radius is proportional to $A^{1/3}$ ,
where $A$ is the mass number of nucleus.
$R = R_{0} A^{1/3}$
where $R_{0} = 1.2 f m$
$\frac{R _{1}}{R _{2}} = \frac{R _{0} ( 216 ) ^{1/3}}{R _{0} ( 125 ) ^{1/3}} = \frac{6}{5}$

Q. The ratio of the nuclear radii of elements with mass numbers 216 and 125 is

216:125

216​:125​

6:5

none of these

Nuclear radius is proportional to A1/3, where A is the mass number of nucleus. R=R0​A1/3 where R0​=1.2fm R2​R1​​=R0​(125)1/3R0​(216)1/3​=56​

Q. The ratio of the nuclear radii of elements with mass numbers $216$ and $125$ is

$216 : 125$

$216 : 125$

$6 : 5$

Nuclear radius is proportional to $A^{1/3}$ ,
where $A$ is the mass number of nucleus.
$R = R_{0} A^{1/3}$
where $R_{0} = 1.2 f m$
$\frac{R _{1}}{R _{2}} = \frac{R _{0} ( 216 ) ^{1/3}}{R _{0} ( 125 ) ^{1/3}} = \frac{6}{5}$