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  4. The ratio of the nuclear radii of elements with mass numbers 216 and 125 is

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Q. The ratio of the nuclear radii of elements with mass numbers $216$ and $125$ is

KCETKCET 2008Nuclei

Solution:

Nuclear radius is proportional to $A^{1 / 3}$,
where $A$ is the mass number of nucleus.
$R=R_{0} A^{1 / 3}$
where $R_{0}=1.2\, fm$
$\frac{R_{1}}{R_{2}}=\frac{R_{0}(216)^{1 / 3}}{R_{0}(125)^{1 / 3}}=\frac{6}{5}$