The ratio of the force between two charges in vacuum at a certain distance apart to that between the same charges, the same distance apart in a medium of permittivity ε is :

Question

The ratio of the force between two charges in vacuum at a certain distance apart to that between the same charges, the same distance apart in a medium of permittivity ε is : (A) ε :1 (B) 1:ε (C) ε0:ε (D) none of the above.

Tardigrade Admin · Accepted Answer

Fvocuum / Fmedium = εr = ε / ε0

Q. The ratio of the force between two charges in vacuum at a certain distance apart to that between the same charges, the same distance apart in a medium of permittivity $ε$ is :

$ε : 1$

$1 : ε$

$ε_{0} : ε$

none of the above.

$F_{v oc uu m} / F_{m e d i u m} = ε_{r} = ε / ε_{0}$

Q. The ratio of the force between two charges in vacuum at a certain distance apart to that between the same charges, the same distance apart in a medium of permittivity ε is :

ε:1

1:ε

ε0​:ε