The ratio of radii of two satellites is p and the ratio of their acceleration due to gravity is q. The ratio of their escape velocities will be :

Question

The ratio of radii of two satellites is p and the ratio of their acceleration due to gravity is q. The ratio of their escape velocities will be : (A) (( q / p ))1 / 2 (B) (( p / q ))1 / 2 (C) pq (D) √ pq

Tardigrade Admin · Accepted Answer

V text escape =√2 gR ( V 1/ V 2)=√( g 1 R 1/ g 2 R 2) =√ pq

Q. The ratio of radii of two satellites is $p$ and the ratio of their acceleration due to gravity is $q$ . The ratio of their escape velocities will be :

$(\frac{q}{p})^{1/2}$

$(\frac{p}{q})^{1/2}$

$pq$

$pq$

$V_{escape} = 2 g R$
$\frac{V _{1}}{V _{2}} = \frac{g _{1} R _{1}}{g _{2} R _{2}}$
$= pq$

Q. The ratio of radii of two satellites is p and the ratio of their acceleration due to gravity is q. The ratio of their escape velocities will be :

(pq​)1/2

(qp​)1/2

pq

pq​

Vescape ​=2gR​ V2​V1​​=g2​R2​g1​R1​​​ =pq​

Q. The ratio of radii of two satellites is $p$ and the ratio of their acceleration due to gravity is $q$ . The ratio of their escape velocities will be :

$(\frac{q}{p})^{1/2}$

$(\frac{p}{q})^{1/2}$

$pq$

$pq$

$V_{escape} = 2 g R$
$\frac{V _{1}}{V _{2}} = \frac{g _{1} R _{1}}{g _{2} R _{2}}$
$= pq$