The ratio of radii of nuclei 1327 Al and 52152 Te is approximately:

Question

The ratio of radii of nuclei 1327 Al and 52152 Te is approximately: (A) 6: 10 (B) 13: 52 (C) 40: 177 (D) 14: 7

Tardigrade Admin · Accepted Answer

The radius of a nucleus of atomic number A is given by R=R0 A1 / 3 where R0 is Bohrs radius. Given, A1=27, A2=125 ∴ (R1/R2)=((27/125))1 / 3 =(3/5)=(6/10)

Q. The ratio of radii of nuclei $_{13}^{27} A l$ and $_{52}^{152} T e$ is approximately:

6 : 10

13 : 52

40 : 177

14 : 7

The radius of a nucleus of atomic number $A$ is given by
$R = R_{0} A^{1/3}$
where $R_{0}$ is Bohrs radius.
Given, $A_{1} = 27$ ,
$A_{2} = 125$
$∴ \frac{R _{1}}{R _{2}} = (\frac{27}{125})^{1/3}$
$= \frac{3}{5} = \frac{6}{10}$

Q. The ratio of radii of nuclei 1327​Al and 52152​Te is approximately: