Question

The ratio of neutrons in $C$ and $Si$ with respective atomic masses 12 and 28 is:

• A. 2: 3
• B. 3: 2
• C. 3: 7
• D. 7: 3

Answer 1

Answer: (C)

Neutrons in ${}_6^{12}C=6$

Neutrons in ${}_{14}^{28}Si=14$

Ratio $:6:14=3:7$