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Chemistry
The ratio of neutrons in C and Si with respective atomic masses 12 and 28 is:
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Q. The ratio of neutrons in $C$ and $Si$ with respective atomic masses 12 and 28 is:
Structure of Atom
A
2: 3
8%
B
3: 2
5%
C
3: 7
83%
D
7: 3
4%
Solution:
Neutrons in ${ }_{6}^{12} C =6$
Neutrons in ${ }_{14}^{28} Si =14$
Ratio $: 6: 14=3: 7$