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Tardigrade
Question
Physics
The ratio of maximum and minimum intensities of two sources is 4:1. The ratio of their amplitudes would be –
Q. The ratio of maximum and minimum intensities of two sources is
4
:
1.
The ratio of their amplitudes would be –
1914
169
NTA Abhyas
NTA Abhyas 2020
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A
1
:
3
B
3
:
1
C
1
:
9
D
1
:
1
Solution:
I
min
I
ma
x
=
1
4
Intensity is directly propotional to square of amplitude.
⇒
A
min
A
ma
x
=
1
2
⇒
A
1
−
A
2
A
1
+
A
2
=
1
2
⇒
A
2
A
1
=
1
3
.