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  4. The ratio of maximum and minimum intensities of two sources is 4:1. The ratio of their amplitudes would be –

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Q. The ratio of maximum and minimum intensities of two sources is $4:1.$ The ratio of their amplitudes would be –

NTA AbhyasNTA Abhyas 2020

Solution:

$\frac{I_{m a x}}{I_{m i n}}=\frac{4}{1}$
Intensity is directly propotional to square of amplitude. $\Rightarrow \frac{A_{m a x}}{A_{m i n}}=\frac{2}{1}\Rightarrow \frac{A_{1} + A_{2}}{A_{1} - A_{2}}=\frac{2}{1}$
$\Rightarrow \frac{A_{1}}{A_{2}}=\frac{3}{1}$ .