The ratio of amplitudes of two coherent waves in Young's double-slit experiment is (A1/A2)=(1/3) . What is the ratio of maximum and minimum intensities of fringes?

Question

The ratio of amplitudes of two coherent waves in Young's double-slit experiment is (A1/A2)=(1/3) . What is the ratio of maximum and minimum intensities of fringes? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(I max /I min )=(√I1+√I22/(√I1-√I2)2)=(A1+3 A1/A1-3 A1) (I max /I min )=(A1+3 A1/A1-3 A1)=(4/2)2=4

Q. The ratio of amplitudes of two coherent waves in Young's double-slit experiment is $\frac{A _{1}}{A _{2}} = \frac{1}{3}$ . What is the ratio of maximum and minimum intensities of fringes?

$\frac{I _{m a x}}{I _{m i n}} = \frac{I _{1} + I _{2} ^{2}}{( I _{1} - I _{2} ) ^{2}} = \frac{A _{1} + 3 A _{1}}{A _{1} - 3 A _{1}}$
$\frac{I _{m a x}}{I _{m i n}} = \frac{A _{1} + 3 A _{1}}{A _{1} - 3 A _{1}} = \frac{4}{2}^{2} = 4$

Q. The ratio of amplitudes of two coherent waves in Young's double-slit experiment is A2​A1​​=31​ . What is the ratio of maximum and minimum intensities of fringes?

Imin​Imax​​=(I1​​−I2​​)2I1​​+I2​​2​=A1​−3A1​A1​+3A1​​ Imin​Imax​​=A1​−3A1​A1​+3A1​​=24​2=4

Q. The ratio of amplitudes of two coherent waves in Young's double-slit experiment is $\frac{A _{1}}{A _{2}} = \frac{1}{3}$ . What is the ratio of maximum and minimum intensities of fringes?

$\frac{I _{m a x}}{I _{m i n}} = \frac{I _{1} + I _{2} ^{2}}{( I _{1} - I _{2} ) ^{2}} = \frac{A _{1} + 3 A _{1}}{A _{1} - 3 A _{1}}$
$\frac{I _{m a x}}{I _{m i n}} = \frac{A _{1} + 3 A _{1}}{A _{1} - 3 A _{1}} = \frac{4}{2}^{2} = 4$