Question

The ratio in which the join of $(2,1,5)$ and $(3,4,3)$ is divided by the plane $(x+y-z)=\frac{1}{2}$ is:

• A. 3 : 5
• B. 5 : 7
• C. 1 : 3
• D. 4 : 5

Answer 1

Answer: (B)

As given plane $x+y-z=\frac{1}{2}$ divides the line joining the points $A(2,1,5)$ and $B(3,4,3)$ at a point $C$ in the ratio $k:1$.
Then coordinates of $C$
$\left(\frac{3k+2}{k+1},\frac{4k+1}{k+1},\frac{3k+5}{k+1}\right)$
Point $C$ lies on the plane,
$\Rightarrow$ Coordinates of $C$ must satisfy the equation of plane.
So, $\left(\frac{3k+2}{k+1}\right)+\left(\frac{4k+1}{k+1}\right)-\left(\frac{3k+5}{k+1}\right)=\frac{1}{2}$
$\Rightarrow 3k+2+4k+1-3k-5=\frac{1}{2}(k+1)$
$\Rightarrow 4k-2=\frac{1}{2}(k+1)$
$\Rightarrow 8k-4=k+1$
$\Rightarrow 7k=5$
$\Rightarrow k=\frac{5}{7}$
Ratio is $5:7$.