Question

The ratio between the neutrons in C and Si with respect to atomic masses 12 and 28 is

• A. $2:3$
• B. $3:2$
• C. $3:7$
• D. $7:3$

Answer 1

Answer: (C)

Neutrons in ${}_6^{12}C=6,$ , Neutrons in ${}_{14}^{28}Si=14$ $\therefore$ Ratio $=6:14=3:7$