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Tardigrade
Question
Chemistry
The rate of the reaction, A+B+C arrow P is given by: r=-(d [A]/ d t) =k [A]1 /2 [B]1 /2 [C]1/ 4⋅ The order of the reaction is
Q. The rate of the reaction,
A
+
B
+
C
→
P
is given by :
r
=
−
d
t
d
[
A
]
=
k
[
A
]
1/2
[
B
]
1/2
[
C
]
1/4
⋅
The order of the reaction is
1664
212
Chemical Kinetics
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A
1
0%
B
2
0%
C
1/2
0%
D
5/4
100%
Solution:
As we know,
For a reaction,
A
+
B
→
Product, if rate
=
K
[
A
]
m
[
B
]
n
, the order of reaction
=
m
+
n
.
So here for the given reaction, order of reaction
=
1/2
+
1/2
+
1/4
=
5/4