The rate of the first-order reaction X→ products is 7.5 × 10-4 mol L-1 min-1. What will be the value of rate constant when the concentration of X is 0.5 mol L-1?

Question

The rate of the first-order reaction X→ products is 7.5 × 10-4 mol L-1 min-1. What will be the value of rate constant when the concentration of X is 0.5 mol L-1? (A) 3.75 × 10-4 s-1 (B) 2.5 × 10-5 s-1 (C) 1.5 × 10-3 s-1 (D) 8.0 × 10-4 s-1

Tardigrade Admin · Accepted Answer

Rate of reaction =7.5×10-4 molL-1min-1 =(7.5×10-4/60)mol L-1s-1 =1.25×10-5mol L-1sec-1 Rate of reaction=k[concentration of reactant X] or k=(1.25×10-5 /0.5)=1.25×10-5s-1

Q. The rate of the first-order reaction $X \to$ products is $7.5 \times 1 0^{- 4} m o l L^{- 1} mi n^{- 1.}$ What will be the value of rate constant when the concentration of $X$ is $0.5 m o l L^{- 1} ?$

$3.75 \times 1 0^{- 4} s^{- 1}$

$2.5 \times 1 0^{- 5} s^{- 1}$

$1.5 \times 1 0^{- 3} s^{- 1}$

$8.0 \times 1 0^{- 4} s^{- 1}$

Q. The rate of the first-order reaction X→ products is 7.5×10−4molL−1min−1. What will be the value of rate constant when the concentration of X is 0.5molL−1?

3.75×10−4s−1

2.5×10−5s−1

1.5×10−3s−1

8.0×10−4s−1

Rate of reaction =7.5×10−4molL−1min−1 =607.5×10−4​molL−1s−1 =1.25×10−5molL−1sec−1 Rate of reaction=k[concentrationofreactantX] or k=0.51.25×10−5​=1.25×10−5s−1

Q. The rate of the first-order reaction $X \to$ products is $7.5 \times 1 0^{- 4} m o l L^{- 1} mi n^{- 1.}$ What will be the value of rate constant when the concentration of $X$ is $0.5 m o l L^{- 1} ?$

$3.75 \times 1 0^{- 4} s^{- 1}$

$2.5 \times 1 0^{- 5} s^{- 1}$

$1.5 \times 1 0^{- 3} s^{- 1}$

$8.0 \times 1 0^{- 4} s^{- 1}$