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Q. The rate of the first-order reaction $X\to$ products is $7.5 \times 10^{-4} mol L^{-1} min^{-1.}$ What will be the value of rate constant when the concentration of $X$ is $0.5\, mol\, L^{-1}?$

Chemical Kinetics

Solution:

Rate of reaction $=7.5\times10^{-4} molL^{-1}min^{-1}$
$=\frac{7.5\times10^{-4}}{60}mol L^{-1}s^{-1}$
$=1.25\times10^{-5}mol\, L^{-1}sec^{-1}$
Rate of reaction$=k\left[concentration \,of\, reactant\, X\right]$
or $k=\frac{1.25\times10^{-5} }{0.5}=1.25\times10^{-5}s^{-1}$