The rate of reaction CCl3CHO+NO xrightarrow[]CHCl3+NO+CO Is equal to rate =k[CCl3CHO][NO] . If concentration is expressed in mol text L-1, the unit of k is

Question

The rate of reaction CCl3CHO+NO xrightarrow[]CHCl3+NO+CO Is equal to rate =k[CCl3CHO][NO] . If concentration is expressed in mol text L-1, the unit of k is (A)  L mol-1s-1  (B)  mol text L-1s-1  (C)  L2mol-2s-1  (D)  s-1

Tardigrade Admin · Accepted Answer

Rate =(dx/dt)=k[CCl3CHO][NO] k=(dx/dt× [CCl3CHO][NO]) =(mol L-1/s-1× mol L-1× mol L-1) =L mol-1s-1

Q. The rate of reaction
$CC l_{3} C H O + NO C H C l_{3} + NO + CO$ Is equal to rate $= k [CC l_{3} C H O] [NO]$ . If concentration is expressed in $m o l L^{- 1},$ the unit of $k$ is

$L m o l^{- 1} s^{- 1}$

$m o l L^{- 1} s^{- 1}$

$L^{2} m o l^{- 2} s^{- 1}$

$s^{- 1}$

Rate $= \frac{d x}{d t} = k [CC l_{3} C H O] [NO]$
$k = \frac{d x}{d t \times [ CC l _{3} C H O ] [ NO ]}$
$= \frac{m o l L ^{- 1}}{s ^{- 1} \times m o l L ^{- 1} \times m o l L ^{- 1}}$
$= L m o l^{- 1} s^{- 1}$

Q. The rate of reaction CCl3​CHO+NO​CHCl3​+NO+CO Is equal to rate =k[CCl3​CHO][NO]. If concentration is expressed in molL−1, the unit of k is

Lmol−1s−1

molL−1s−1

L2mol−2s−1

s−1