Question

The rate of reaction
$ CC{{l}_{3}}CHO+NO\xrightarrow[{}]{{}}CHC{{l}_{3}}+NO+CO $ Is equal to rate $ =k[CC{{l}_{3}}CHO][NO] $. If concentration is expressed in $ mol\text{ }{{L}^{-1}}, $ the unit of $ k $ is

• A. $ L\,mo{{l}^{-1}}{{s}^{-1}} $
• B. $ mol\text{ }{{L}^{-1}}{{s}^{-1}} $
• C. $ {{L}^{2}}mo{{l}^{-2}}{{s}^{-1}} $
• D. $ {{s}^{-1}} $

Answer 1

Answer: (A)

Rate $ =\frac{dx}{dt}=k[CC{{l}_{3}}CHO][NO] $
$ k=\frac{dx}{dt\times [CC{{l}_{3}}CHO][NO]} $
$ =\frac{mol\,{{L}^{-1}}}{{{s}^{-1}}\times mol\,{{L}^{-1}}\times mol\,{{L}^{-1}}} $
$ =L\,mo{{l}^{-1}}{{s}^{-1}} $