The rate of reaction between A and B increases by a factor of 100, when the concentration of A is increased 10 folds. The order of reaction with respect to A is

Question

The rate of reaction between A and B increases by a factor of 100, when the concentration of A is increased 10 folds. The order of reaction with respect to A is (A) 10 (B) 1 (C) 4 (D) 2

Tardigrade Admin · Accepted Answer

r=K[A]n,100r=K[10A]n (1/100)=((1/10))n or n=2

Q. The rate of reaction between $A$ and $B$ increases by a factor of $100,$ when the concentration of $A$ is increased $10$ folds. The order of reaction with respect to $A$ is

$10$

$1$

$4$

$2$

$r = K [A]^{n}, 10 0_{r} = K [10 A]^{n}$
$\frac{1}{100} = (\frac{1}{10})^{n}$ or $n = 2$

Q. The rate of reaction between A and B increases by a factor of 100, when the concentration of A is increased 10 folds. The order of reaction with respect to A is

10

1

4

2

r=K[A]n,100r​=K[10A]n 1001​=(101​)n or n=2

Q. The rate of reaction between $A$ and $B$ increases by a factor of $100,$ when the concentration of $A$ is increased $10$ folds. The order of reaction with respect to $A$ is

$10$

$1$

$4$

$2$

$r = K [A]^{n}, 10 0_{r} = K [10 A]^{n}$
$\frac{1}{100} = (\frac{1}{10})^{n}$ or $n = 2$