The rate of reaction A + 2B→ 3C gets increased by 72 times when the concentration of A is tripled and that of B is doubled. The order of the reaction with respect to A and B are.....and.....respectively

Question

The rate of reaction A + 2B→ 3C gets increased by 72 times when the concentration of A is tripled and that of B is doubled. The order of the reaction with respect to A and B are.....and.....respectively (A) 1,2 (B) 2,3 (C) 3,2 (D) 2, 2

Tardigrade Admin · Accepted Answer

r=k[A]α[B]β....(i) 72 r=k[3A]α[2B]β.....(ii) Dividing eqn. (1) by eqn. (h) 72 = 3α2β By substituting the given values of α = 2, β=3, we have 3α× 2β=32 × 23=9 × 8 =72

Q. The rate of reaction A + 2B $\to$ 3C gets increased by 72 times when the concentration of A is tripled and that of B is doubled. The order of the reaction with respect to A and B are.....and.....respectively

1,2

2,3

3,2

2, 2

$r = k [A]^{α} [B]^{β}$ ....(i)
72 r=k $[3 A]^{α} [2 B]^{β}$ .....(ii)
Dividing eqn. (1) by eqn. (h) 72 = $3^{α} 2^{β}$ By substituting the given values of $α = 2, β = 3,$ we have
$3^{α} \times 2^{β} = 3^{2} \times 2^{3} = 9 \times 8 = 72$

Q. The rate of reaction A + 2B→ 3C gets increased by 72 times when the concentration of A is tripled and that of B is doubled. The order of the reaction with respect to A and B are.....and.....respectively

1,2

2,3

3,2

2, 2

r=k[A]α[B]β....(i) 72 r=k[3A]α[2B]β.....(ii) Dividing eqn. (1) by eqn. (h) 72 = 3α2β By substituting the given values of α=2,β=3, we have 3α×2β=32×23=9×8=72

Q. The rate of reaction A + 2B $\to$ 3C gets increased by 72 times when the concentration of A is tripled and that of B is doubled. The order of the reaction with respect to A and B are.....and.....respectively

$r = k [A]^{α} [B]^{β}$ ....(i)
72 r=k $[3 A]^{α} [2 B]^{β}$ .....(ii)
Dividing eqn. (1) by eqn. (h) 72 = $3^{α} 2^{β}$ By substituting the given values of $α = 2, β = 3,$ we have
$3^{α} \times 2^{β} = 3^{2} \times 2^{3} = 9 \times 8 = 72$