"The rate of loss of heat -dQ/dt of the body is directly proportional to the temperature difference Δ T = (T2 - T1) of the body and surroundings". This statement is

Question

"The rate of loss of heat -dQ/dt of the body is directly proportional to the temperature difference Δ T = (T2 - T1) of the body and surroundings". This statement is (A) law of thermometry (B) Newtons law of cooling (C) law of calorimetry (D) zeroth law

Tardigrade Admin · Accepted Answer

The rate of loss of heat of a body is represented as:

-\frac{ d Q}{ dt } \propto T _{2}- T _{1}

This statement is Newton's law of cooling where the rate of loss of heat is directly proportional to the temperature difference between the body and the surroundings.

Q. "The rate of loss of heat −dQ/dt of the body is directly proportional to the temperature difference ΔT=(T2​−T1​) of the body and surroundings". This statement is

law of thermometry

Newtons law of cooling

law of calorimetry

zeroth law

The rate of loss of heat of a body is represented as: -\frac{ d Q}{ dt } \propto T _{2}- T _{1} This statement is Newton's law of cooling where the rate of loss of heat is directly proportional to the temperature difference between the body and the surroundings.

Q. "The rate of loss of heat $- d Q / d t$ of the body is directly proportional to the temperature difference $Δ T = (T_{2} - T_{1})$ of the body and surroundings". This statement is

The rate of loss of heat of a body is represented as:

-\frac{ d Q}{ dt } \propto T _{2}- T _{1}

This statement is Newton's law of cooling where the rate of loss of heat is directly proportional to the temperature difference between the body and the surroundings.