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Tardigrade
Question
Chemistry
The rate of forward reaction is two times that of the reverse reaction at a given temperature and identical concentration, K equilibrium is
Q. The rate of forward reaction is two times that of the reverse reaction at a given temperature and identical concentration, K equilibrium is
2838
192
KEAM
KEAM 2002
Equilibrium
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A
0.5
18%
B
1.5
12%
C
2.5
16%
D
2.0
54%
Solution:
K
e
q
=
K
f
K
b
= 2/1 =2