1. Tardigrade
  2. Question
  3. Chemistry
  4. The rate of forward reaction is two times that of the reverse reaction at a given temperature and identical concentration, K equilibrium is

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Q. The rate of forward reaction is two times that of the reverse reaction at a given temperature and identical concentration, K equilibrium is

KEAMKEAM 2002Equilibrium

Solution:

$K_{eq} = K_fK_b$ = 2/1 =2