The rate of formation of SO3 in the following reaction: 2SO2 + O2 → 2SO3 is 10 g sec-1. The rate of disappearance of O2 will be

Question

The rate of formation of SO3 in the following reaction: 2SO2 + O2 → 2SO3 is 10 g sec-1. The rate of disappearance of O2 will be (A) 5 g sec-1 (B) 100 g sec-1 (C) 20 g sec-1 (D) 2 g sec-1

Tardigrade Admin · Accepted Answer

2SO2 + O2 → 2SO3 rSO3=10 g/sec=(10/80) mol/sec Also, (rO2/1)=(rSO3/2)⇒ rO2=(10/80)×(1/2) mol/ sec =((10/160))×32g/sec =2 g/sec

Q. The rate of formation of $S O_{3}$ in the following reaction: $2 S O_{2} + O_{2} \to 2 S O_{3}$ is $10 g se c^{- 1}$ . The rate of disappearance of $O_{2}$ will be

$5 g se c^{- 1}$

$100 g se c^{- 1}$

$20 g se c^{- 1}$

$2 g se c^{- 1}$

$2 S O_{2} + O_{2} \to 2 S O_{3}$
$r_{S O_{3}} = 10 g / sec = \frac{10}{80} m o l / sec$
Also, $\frac{r _{O_{2}}}{1} = \frac{r _{S O_{3}}}{2} \Rightarrow r_{O_{2}} = \frac{10}{80} \times \frac{1}{2} m o l / sec$
$= (\frac{10}{160}) \times 32 g / sec = 2 g / sec$

Q. The rate of formation of SO3​ in the following reaction: 2SO2​+O2​→2SO3​ is 10gsec−1. The rate of disappearance of O2​ will be

5gsec−1

100gsec−1

20gsec−1

2gsec−1