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Q. The rate of formation of $SO_3$ in the following reaction: $2SO_2 + O_2 \to 2SO_3$ is $10\, g\, sec^{-1}$. The rate of disappearance of $O_2$ will be

Chemical Kinetics

Solution:

$2SO_2 + O_2 \to 2SO_3$
$r_{SO_3}=10 g/sec=\frac{10}{80} mol/sec$
Also, $\frac{r_{O_2}}{1}=\frac{r_{SO_3}}{2}\Rightarrow r_{O_2}=\frac{10}{80}\times\frac{1}{2} mol/ sec$
$=\left(\frac{10}{160}\right)\times32g/sec =2 g/sec$