Question

The rate of chemisorption of a gas

• A. decreases with increasing pressure
• B. increases with increasing pressure
• C. is independent of pressure
• D. is independent of temperature

Answer 1

Answer: (B)

Rate of chemisorption of a gas increases with gas increases in pressure because more molecules are adsorbed on the surface at higher pressure. This can also understood by the following relation:
$\log \frac{x}{m}=\log K+\frac{1}{n}\log p$
where, $\frac{x}{m}$= mass adsorbed over per unit surface of adsorbent
$n$ and $k$ are constants $p$= pressure,
i.e., $\frac{x}{m}\propto p$