The rate law for the reaction below is given by the expression k [A][B] A + B → Product If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :

Question

The rate law for the reaction below is given by the expression k [A][B] A + B → Product If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be : (A) k (B) k/3 (C) 3k (D) 9k

Tardigrade Admin · Accepted Answer

rate constant is independent of concentration.

Q. The rate law for the reaction below is given by the expression k [A][B] A + B → Product If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :

k

k/3

3k

9k

rate constant is independent of concentration.

Q. The rate law for the reaction below is given by the expression k [A][B]
A + B $\to$ Product
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :