The rate law for the reaction, 2X+Y→ Z is Rate=k [X][Y]. The correct statement with regard to this relation is

Question

The rate law for the reaction, 2X+Y→ Z is Rate=k [X][Y]. The correct statement with regard to this relation is (A) the rate of reaction is independent of [X] and [V] (B) for this reaction t1/2 is independent of initial concentration of reactants (C) the unit of k is S-1  (D) the rate of formation of Z is half the rate of disappearance of X

Tardigrade Admin · Accepted Answer

2X+Y→ Z According to equation, 2 moles of X on reaction with 1 mole of Y gives 1 mole of Z. In other words, the rate of formation of Z is half the rate of disappearance of X.

Q. The rate law for the reaction, $2 X + Y \to Z$ is $R a t e = k [X] [Y] .$ The correct statement with regard to this relation is

the rate of reaction is independent of [X] and [V]

for this reaction $t_{1/2}$ is independent of initial concentration of reactants

the unit of $k$ is $S^{- 1}$

the rate of formation of Z is half the rate of disappearance of X

$2 X + Y \to Z$ According to equation, 2 moles of X on reaction with 1 mole of Y gives 1 mole of Z. In other words, the rate of formation of Z is half the rate of disappearance of X.

Q. The rate law for the reaction, 2X+Y→Z is Rate=k[X][Y]. The correct statement with regard to this relation is

the rate of reaction is independent of [X] and [V]

for this reaction t1/2​ is independent of initial concentration of reactants

the unit of k is S−1

the rate of formation of Z is half the rate of disappearance of X

2X+Y→Z According to equation, 2 moles of X on reaction with 1 mole of Y gives 1 mole of Z. In other words, the rate of formation of Z is half the rate of disappearance of X.

Q. The rate law for the reaction, $2 X + Y \to Z$ is $R a t e = k [X] [Y] .$ The correct statement with regard to this relation is

for this reaction $t_{1/2}$ is independent of initial concentration of reactants

the unit of $k$ is $S^{- 1}$

$2 X + Y \to Z$ According to equation, 2 moles of X on reaction with 1 mole of Y gives 1 mole of Z. In other words, the rate of formation of Z is half the rate of disappearance of X.