The rate constant of the reaction A arrow B is 0.6× 10- 3molelitre - 1sec- 1 . If the concentration of A is 5M , then concentration of B after 20 minutes is:

Question

The rate constant of the reaction A arrow B is 0.6× 10- 3molelitre - 1sec- 1 . If the concentration of A is 5M , then concentration of B after 20 minutes is: (A) 0.36M (B) 0.72M (C) 1.08M (D) 3.60M

Tardigrade Admin · Accepted Answer

For zero order reaction: x=K.t =0.6× 10- 3× 20× 60 x=0.72M

Q. The rate constant of the reaction $A \to B$ is $0.6 \times 1 0^{- 3} m o l e l i t re_^{- 1} se c_{- 1}$ . If the concentration of $A$ is $5 M$ , then concentration of $B$ after 20 minutes is:

$0.36 M$

$0.72 M$

$1.08 M$

$3.60 M$

For zero order reaction :
$x = K . t$
$= 0.6 \times 1 0^{- 3} \times 20 \times 60$
$x = 0.72 M$

Q. The rate constant of the reaction A→B is 0.6×10−3molelitre_−1sec−1​ . If the concentration of A is 5M , then concentration of B after 20 minutes is:

0.36M

0.72M

1.08M

3.60M