The rate constant of the reaction A → B is 0.6 × 10-3 mole per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is :

Question

The rate constant of the reaction A → B is 0.6 × 10-3 mole per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is : (A) 0.36 M (B) 0.72 M (C) 1.08 M (D) 3.60 M

Tardigrade Admin · Accepted Answer

For zero order reaction: x = K.t = 0.6 × 10-3 × 20 × 60 x = 0.72 M

Q. The rate constant of the reaction $A \to B$ is $0.6 \times 1 0^{- 3}$ mole per second. If the concentration of A is 5 M, then concentration of $B$ after 20 minutes is :

0.36 M

0.72 M

1.08 M

3.60 M

For zero order reaction :
x = K.t
= $0.6 \times 1 0^{- 3} \times 20 \times 60$
x = 0.72 M

Q. The rate constant of the reaction A→B is 0.6×10−3 mole per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is :