The rate constant of the reaction 2H2O2 (a q) arrow 2H2O (l)+ O2 (g)is 3 × (10)- 3(m i n)- 1 At what concentration of H2O2 , the rate of the reaction will be 2 × 10- 4 Ms- 1 ?

Question

The rate constant of the reaction 2H2O2 (a q) arrow 2H2O (l)+ O2 (g)is 3 × (10)- 3(m i n)- 1 At what concentration of H2O2 , the rate of the reaction will be 2 × 10- 4 Ms- 1 ? (A) 6.67 × 10- 3 M (B) 2 M (C) 4 M (D) 0.08 M

Tardigrade Admin · Accepted Answer

-(d [H2 O2]/d t)=k[H2 O2]1 ∴ 2× 10- 4=(3 × 10- 3/60)× [H2 O2] or [H2 O2]=4 M

Q. The rate constant of the reaction
$2 H_{2} O_{2} (a q) \to 2 H_{2} O (l) + O_{2} (g) i s 3 \times (10)^{- 3} (min)^{- 1}$
At what concentration of $H_{2} O_{2},$ the rate of the reaction will be $2 \times 1 0^{- 4} M s^{- 1}$ ?

$6.67 \times 1 0^{- 3} M$

2 M

4 M

0.08 M

$- \frac{d [ H _{2} O _{2} ]}{d t} = k [H_{2} O_{2}]^{1}$
$∴ 2 \times 1 0^{- 4} = \frac{3 \times 1 0 ^{- 3}}{60} \times [H_{2} O_{2}]$
$or [H_{2} O_{2}] = 4 M$

Q. The rate constant of the reaction 2H2​O2​(aq)→2H2​O(l)+O2​(g)is3×(10)−3(min)−1 At what concentration of H2​O2​, the rate of the reaction will be 2×10−4Ms−1 ?

6.67×10−3M

2 M

4 M

0.08 M

−dtd[H2​O2​]​=k[H2​O2​]1 ∴2×10−4=603×10−3​×[H2​O2​] or[H2​O2​]=4M

Q. The rate constant of the reaction
$2 H_{2} O_{2} (a q) \to 2 H_{2} O (l) + O_{2} (g) i s 3 \times (10)^{- 3} (min)^{- 1}$
At what concentration of $H_{2} O_{2},$ the rate of the reaction will be $2 \times 1 0^{- 4} M s^{- 1}$ ?

$6.67 \times 1 0^{- 3} M$

$- \frac{d [ H _{2} O _{2} ]}{d t} = k [H_{2} O_{2}]^{1}$
$∴ 2 \times 1 0^{- 4} = \frac{3 \times 1 0 ^{- 3}}{60} \times [H_{2} O_{2}]$
$or [H_{2} O_{2}] = 4 M$