The rate constant of a reaction is given by k=P Ze-Ea/RT under standard notation. In order to speed up the reaction, which of the following factors has to be decreased ?

Question

The rate constant of a reaction is given by k=P Ze-Ea/RT under standard notation. In order to speed up the reaction, which of the following factors has to be decreased ? (A) Z (B) Both Z and T (C) Ea (D) T

Tardigrade Admin · Accepted Answer

The expression of rate constant given in the question ( .k = PZ e (- Ea / RT )) is according to Arrhenius theory. To speed up the reaction, we will have to decrease the value of Ea i.e. activation energy and will have to increase the value of temperature (T) and the number of collisions (Z).

Q. The rate constant of a reaction is given by $k = PZ e^{- E a / RT}$ under standard notation. In order to speed up the reaction, which of the following factors has to be decreased ?

Z

Both Z and T

$E_{a}$

T

Q. The rate constant of a reaction is given by k=PZe−Ea/RT under standard notation. In order to speed up the reaction, which of the following factors has to be decreased ?

Z

Both Z and T

Ea​

T

The expression of rate constant given in the question ( k=PZe(−Ea/RT)) is according to Arrhenius theory. To speed up the reaction, we will have to decrease the value of Ea​ i.e. activation energy and will have to increase the value of temperature (T) and the number of collisions (Z).

Q. The rate constant of a reaction is given by $k = PZ e^{- E a / RT}$ under standard notation. In order to speed up the reaction, which of the following factors has to be decreased ?

$E_{a}$