The rate constant of a first order reaction is 231 × 10-5 s-1. How long will 4 g of this reactant reduce to 2 g?

Question

The rate constant of a first order reaction is 231 × 10-5 s-1. How long will 4 g of this reactant reduce to 2 g? (A) 310 s (B) 300 s (C) 210 s (D) 30.1 s

Tardigrade Admin · Accepted Answer

K=231 × 10-5 S-1 t1 / 2=(0.693/231 × 10-5)=300 S

Q. The rate constant of a first order reaction is $231 \times 1 0^{- 5} s^{- 1}$ . How long will $4 g$ of this reactant reduce to $2 g$ ?

$310 s$

$300 s$

$210 s$

$30.1 s$

$230.3 s$

$K = 231 \times 1 0^{- 5} S^{- 1}$
$t_{1/2} = \frac{0.693}{231 \times 1 0 ^{- 5}} = 300 S$

Q. The rate constant of a first order reaction is 231×10−5s−1. How long will 4g of this reactant reduce to 2g?

310s

300s

210s

30.1s

230.3s

K=231×10−5S−1 t1/2​=231×10−50.693​=300S