The rate constant is doubled when temperature increases from 27 ° C to 37 ° C. Activation energy in kJ is

Question

The rate constant is doubled when temperature increases from 27 ° C to 37 ° C. Activation energy in kJ is (A) 34 (B) 54 (C) 100 (D) 50

Tardigrade Admin · Accepted Answer

log (K3/K1)=(Ea/2.303R)[(1/T1)-(1/T2)]; If (K2/K1)=2 log 2=(Ea/2.303×8.314)[(1/300)-(1/310)] Ea=0.3010 Ã 2.303 Ã 8.314((300×310/10)) =53598.59 Jmol-1=54 kj

Q. The rate constant is doubled when temperature increases from $27^{\circ} C$ to $37^{\circ} C$ . Activation energy in $k J$ is

$34$

$54$

$100$

$50$

Q. The rate constant is doubled when temperature increases from 27∘C to 37∘C. Activation energy in kJ is

34

54

100

50

logK1​K3​​=2.303REa​​[T1​1​−T2​1​];IfK1​K2​​=2 log2=2.303×8.314Ea​​[3001​−3101​]<br/>Ea​=0.3010×2.303×8.314(10300×310​) =53598.59Jmol−1=54kj

Q. The rate constant is doubled when temperature increases from $27^{\circ} C$ to $37^{\circ} C$ . Activation energy in $k J$ is

$34$

$54$

$100$

$50$