Q.
The range of the function f(x)=2x2−11x+12exlnx5(x2+2)(x2−7x+10) is
100
133
Relations and Functions - Part 2
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Solution:
f(x)=(2x−3)(x−4)exlnx5(x2+2)⋅(x−2)(x−5)
Note that at x=3/2 and x=4 function is not defined and in open interval (3/2,4) function is continuous. x→23+Lim=(+ve)(−ve)(+ve)(−ve)(−ve)→−∞ x→4−Lim=(+ve)(−ve)(+ve)(+ve)(−ve)→∞
In the open interval (3/2,4) the function is continuous and takes up all real values from (−∞,∞) Hence range of the function is (−∞,∞) or R