The radius of two metallic spheres A and B are r1 and r2 respectively (r1r2). They are connected by a thin wire and the system is given a certain charge. The charge will be greater

Question

The radius of two metallic spheres A and B are r1 and r2 respectively (r1>r2). They are connected by a thin wire and the system is given a certain charge. The charge will be greater (A) equal on both (B) zero on both (C) on the surface of sphere A (D) on the surface of sphere B

Tardigrade Admin · Accepted Answer

When the spheres are connected by a wire, then potential on both becomes equal. ∴ (Q1/r1)=(Q2/r2) ⇒ (Q1/Q2)=(r1/r2) When r1>r2, then Q1>Q2

Q. The radius of two metallic spheres A and B are $r_{1}$ and $r_{2}$ respectively $(r_{1} > r_{2}) .$ They are connected by a thin wire and the system is given a certain charge. The charge will be greater

equal on both

zero on both

on the surface of sphere A

on the surface of sphere B

When the spheres are connected by a wire, then potential on both becomes equal.
$∴$ $\frac{Q _{1}}{r _{1}} = \frac{Q _{2}}{r _{2}}$
$\Rightarrow$ $\frac{Q _{1}}{Q _{2}} = \frac{r _{1}}{r _{2}}$
When $r_{1} > r_{2},$ then $Q_{1} > Q_{2}$

Q. The radius of two metallic spheres A and B are r1​ and r2​ respectively (r1​>r2​). They are connected by a thin wire and the system is given a certain charge. The charge will be greater